10-1/2t^2=0

Solution for 10-1/2t^2=0 equation:

10-1/2t^2=0


Domain of the equation: 2t^2!=0

t^2!=0/2

t^2!=√0

t!=0

t∈R


We multiply all the terms by the denominator


10*2t^2-1=0

Wy multiply elements

20t^2-1=0

a = 20; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·20·(-1)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{5}}{2*20}=\frac{0-4\sqrt{5}}{40}
=-\frac{4\sqrt{5}}{40}
=-\frac{\sqrt{5}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{5}}{2*20}=\frac{0+4\sqrt{5}}{40}
=\frac{4\sqrt{5}}{40}
=\frac{\sqrt{5}}{10}
$